Answer: [tex] {(1.01)}^{2} \: \: \: \: \: \: \\ {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} \\ = {(1 + 0.01) }^{2} \\ = {1}^{2} + (2 \times 1 \times 0.01) + {0.01}^{2} \\ = 1 + 0.02 + 0.0001 \\ = 1.0201 \\ [/tex] Step-by-step explanation: Plz mark my answer as brainliest plz thank also and don’t forget to follow so that you get your answers in a jiffy. Reply
Answer:
[tex] {(1.01)}^{2} \: \: \: \: \: \: \\ {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} \\ = {(1 + 0.01) }^{2} \\ = {1}^{2} + (2 \times 1 \times 0.01) + {0.01}^{2} \\ = 1 + 0.02 + 0.0001 \\ = 1.0201 \\ [/tex]
Step-by-step explanation:
Plz mark my answer as brainliest plz thank also and don’t forget to follow so that you get your answers in a jiffy.
Answer:
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