Simplify:[tex] \frac{ {3}^{2n + 4} – {5.3}^{2(n + 1)} }{ {(9)}^{n – 1} } [/tex] About the author Isabella
[tex]{\huge {\red {\mid{ \fbox{ \tt{Question}} \mid}}}}[/tex] Simplify: [tex]\frac{ {3}^{2n + 4} – {5.3}^{2(n + 1)} }{ {(9)}^{n – 1} }[/tex] [tex]{\huge {\red {\mid{ \fbox{ \tt{Solution}} \mid}}}}[/tex] [tex]\frac{ {3}^{2n + 4} – {5.3}^{2(n + 1)} }{ {(9)}^{n – 1} }[/tex] [tex] = \frac{ {3}^{2n}. {3}^{4} – {5.3}^{2n} . {3}^{2} }{ {({3}^{2}) }^{n – 1} } [/tex] [tex] = \frac{ {3}^{2n} .81 – {3}^{2n}.45 }{ {3}^{2n} . {3}^{ – 2} } [/tex] [tex] = \frac{ {3}^{2n}.(81 – 45) \times {3}^{2} }{ {3}^{2n} } [/tex] [tex] = 36 \times 9 = \bf{324}[/tex] Reply
[tex]{\huge {\red {\mid{ \fbox{ \tt{Question}} \mid}}}}[/tex]
Simplify:
[tex]\frac{ {3}^{2n + 4} – {5.3}^{2(n + 1)} }{ {(9)}^{n – 1} }[/tex]
[tex]{\huge {\red {\mid{ \fbox{ \tt{Solution}} \mid}}}}[/tex]
[tex]\frac{ {3}^{2n + 4} – {5.3}^{2(n + 1)} }{ {(9)}^{n – 1} }[/tex]
[tex] = \frac{ {3}^{2n}. {3}^{4} – {5.3}^{2n} . {3}^{2} }{ {({3}^{2}) }^{n – 1} } [/tex]
[tex] = \frac{ {3}^{2n} .81 – {3}^{2n}.45 }{ {3}^{2n} . {3}^{ – 2} } [/tex]
[tex] = \frac{ {3}^{2n}.(81 – 45) \times {3}^{2} }{ {3}^{2n} } [/tex]
[tex] = 36 \times 9 = \bf{324}[/tex]