Answer: [tex] \huge{ \red{꧁ℬཞØＫℰη_ℋAℜƬ♡꧂}}[/tex] [tex]3x – 5 – x + 9 \\ \rightarrow \: 2x + 4 \: \: \: \: \: \: \: \: \: \: \\ \bold{x = 3} \: \bold{(given)} \\ \rightarrow \: 2 \times 3 + 4 \: \: \: \: \: \\ \rightarrow \: 6 + 4 \: \: \: \: \: \: \: \: \: \: \: \: \\ \rightarrow \: 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex] Reply
Given :– 3x – 5 – x + 9 x = 3 To find :– The value of the expression Solution :– Simplification: [tex]\implies \bf 3x – 5 – x + 9 \\\\\\ \bf \implies 3x – x + 9 – 5 \\\\\\ \bf \implies 2x + 4 \\\\\\ \dagger \frak { \: Putting \: the \: values \: given \: in \: the \: data} \\ \\ \\ \bf \implies 2(3) + 4 \\\\\\ \implies \bf 6 + 4 \\\\\\ \implies \boxed{\bf 10}[/tex] Therefore, The value of the expression is 10. Verification: [tex] \bf \implies 3x – 5 – x + 9 \\ \\ \\ \bf \implies 3(3) – 5 – (3) + 9 \\ \\ \\ \bf \implies 9 – 5 – 3 + 9 \\ \\ \\ \bf \implies 4 – 3 + 9 \\ \\ \\ \bf \implies 1 + 9 \\ \\ \\ \implies \boxed{\bf 10}[/tex] Hence, Verified! Know more: [tex]\boxed{\begin{array} {c|c} \sf{ +,- } & \sf{ – } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad}{} \\ \sf{- , +} & \sf{ – } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad}{} \\ \sf{+,+} & \sf{ + } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad }{} \\ \sf{-,-} & \sf{ + }\end{array}}[/tex] Reply
Answer:
[tex] \huge{ \red{꧁ℬཞØＫℰη_ℋAℜƬ♡꧂}}[/tex]
[tex]3x – 5 – x + 9 \\ \rightarrow \: 2x + 4 \: \: \: \: \: \: \: \: \: \: \\ \bold{x = 3} \: \bold{(given)} \\ \rightarrow \: 2 \times 3 + 4 \: \: \: \: \: \\ \rightarrow \: 6 + 4 \: \: \: \: \: \: \: \: \: \: \: \: \\ \rightarrow \: 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
Given :–
To find :–
Solution :–
Simplification:
[tex]\implies \bf 3x – 5 – x + 9 \\\\\\ \bf \implies 3x – x + 9 – 5 \\\\\\ \bf \implies 2x + 4 \\\\\\ \dagger \frak { \: Putting \: the \: values \: given \: in \: the \: data} \\ \\ \\ \bf \implies 2(3) + 4 \\\\\\ \implies \bf 6 + 4 \\\\\\ \implies \boxed{\bf 10}[/tex]
Therefore, The value of the expression is 10.
Verification:
[tex] \bf \implies 3x – 5 – x + 9 \\ \\ \\ \bf \implies 3(3) – 5 – (3) + 9 \\ \\ \\ \bf \implies 9 – 5 – 3 + 9 \\ \\ \\ \bf \implies 4 – 3 + 9 \\ \\ \\ \bf \implies 1 + 9 \\ \\ \\ \implies \boxed{\bf 10}[/tex]
Hence, Verified!
Know more:
[tex]\boxed{\begin{array} {c|c} \sf{ +,- } & \sf{ – } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad}{} \\ \sf{- , +} & \sf{ – } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad}{} \\ \sf{+,+} & \sf{ + } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad }{} \\ \sf{-,-} & \sf{ + }\end{array}}[/tex]