show that the difference of a two digit number and the number obtained by reversing digits is a multiple of 9 About the author Maya
Step-by-step explanation: Let the two digit no. be XY ie., 10x+y and it’s reverse be yx i.e,10y+x Their difference=10x+y-(10y+x) =10x+y-10y-x =9x-9y =9(x-y) Therefore their difference is a multiple of 9 H.p Reply
Step-by-step explanation:
Let the two digit no. be XY ie., 10x+y
and it’s reverse be yx i.e,10y+x
Their difference=10x+y-(10y+x)
=10x+y-10y-x
=9x-9y
=9(x-y)
Therefore their difference is a multiple of 9
H.p