Seg CD is the median of ∆ABC. Point D is the midpoint of Seg AB. Then A(∆ADC)/A(∆BDC) = .​

1 thought on “Seg CD is the median of ∆ABC. Point D is the midpoint of Seg AB. Then A(∆ADC)/A(∆BDC) = .​”

1. Answer:

   the answer is abcd

   I don’t know the answer

   mark me as the brainliest

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