Riya runs around a square park of side 70 m. Rahul runs around a rectangular park with length 50 m and breadth 45 m. Who cov

Riya runs around a square park of side 70 m. Rahul runs around a rectangular park with length 50 m and breadth 45 m. Who covers less
distance?​

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2 thoughts on “<br />Riya runs around a square park of side 70 m. Rahul runs around a rectangular park with length 50 m and breadth 45 m. Who cov”

  1. Answer:

    Rahul

    Step-by-step explanation:

    The perimeter of square park is 70×4 = 280m

    Riya run 280 m

    Perimeter of rectangular park is 2 (50+45) =190m

    Rahul runs 190m

    so he covers less distance

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  2. [tex]\large\sf\underline{Given\::}[/tex]

    • Length of square park covered by Riya = 70 m

    • Length and breadth of rectangular park covered by Rahul = 50 m and 45 m respectively

    [tex]\large\sf\underline{To\:find\::}[/tex]

    • Who covers less distance between Riya and Rahul ?

    [tex]\large\sf\underline{Concept\:to\:be\:used\::}[/tex]

    Here we are given the Length of square park covered by Riya as 70 m and Length and breadth of rectangular park covered by Rahul as 50 m and 45 m respectively . We are asked to find who covers less distance . Therefore we would first calculate the distance covered by Riya and then by Rahul so that it would be easier for us to compare and find who would cover less distance . So let’s begin !

    [tex]\large\sf\underline{Formula\:to\:be\:used\::}[/tex]

    • Perimeter of square = [tex]\sf\:4 \times side[/tex]

    • Perimeter of rectangle =[tex]\sf\:2(length + breadth)[/tex]

    [tex]\large\sf\underline{Solution\::}[/tex]

    Let’s first calculate the distance covered by Riya.

    We know :

    [tex]\sf\:Distance\:covered\:by\:Riya\:=\:Perimeter\:of\:square[/tex]

    • Using the formula for perimeter

    [tex]\sf\to\:Distance\:covered\:by\:Riya\:=\:4 \times side[/tex]

    • Substituiting the value of side of square

    [tex]\sf\to\:Distance\:covered\:by\:Riya\:=\:4 \times 70[/tex]

    [tex]\small{\underline{\boxed{\mathrm\red{\to\:Distance\:covered\:by\:Riya\:=280\:m}}}}[/tex] ✧

    Now let’s calculate the distance covered by Rahul.

    We know :

    [tex]\sf\:Distance\:covered\:by\:Rahul\:=\:Perimeter\:of\:rectangle[/tex]

    • Using the formula for perimeter

    [tex]\sf\to\:Distance\:covered\:by\:Rahul\:=\:2(l+b)[/tex]

    • Substituiting the value of l and b

    [tex]\sf\to\:Distance\:covered\:by\:Rahul\:=\:2(50+45)[/tex]

    [tex]\sf\to\:Distance\:covered\:by\:Rahul\:=\:2(95)[/tex]

    [tex]\small{\underline{\boxed{\mathrm\red{\to\:Distance\:covered\:by\:Rahul\:=190\:m}}}}[/tex] ✧

    So we got distance covered by Riya as [tex]\tt\blue{280\:m}[/tex] and distance covered by Rahul as [tex]\tt\blue{190\:m}[/tex]

    Clearly , Less distance is covered by Rahul .

    ‎__________________

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    !! Hope it helps !!

    Reply

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