The flour in a bag is divided into three portions in the ratio of 2:5:7. If the smallest portion weighs 40 kg, how
much heavi

Question

The flour in a bag is divided into three portions in the ratio of 2:5:7. If the smallest portion weighs 40 kg, how
much heavier is the largest portion than the smallest portion​

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Athena 3 months 2021-07-21T01:07:52+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-21T01:09:23+00:00

    Let the largest portion be as x

    then according. to the question …

    2:5:7 will be assumed as….

    2+5+7= 14

    2/14 of x = 40

    = x = 40*14/2

    = x =280kg

    then respectively

    112kg

    and 80kg

    therefore…

    280 – 40

    = 220 kg

    0
    2021-07-21T01:09:27+00:00

    Answer:

    1 portion weighs = 40 kg

    2nd portion weighs = 200kg

    3rd portion weighs = 280 kg

    Step-by-step explanation:

    so the 2nd portion weighs 40×5

    = 200 kg

    the third portion weighs =

    40×7=

    280 kg respectively

    Hope it will help u.

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