Seg CD is the median of ∆ABC. Point D is the midpoint of Seg AB. Then A(∆ADC)/A(∆BDC) = .​

Question

Seg CD is the median of ∆ABC. Point D is the midpoint of Seg AB. Then A(∆ADC)/A(∆BDC) = .​

in progress 0
Emery 3 months 2021-07-19T20:27:09+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-19T20:28:51+00:00

    Answer:

    the answer is abcd

    I don’t know the answer

    mark me as the brainliest

Leave an answer

Browse

9:3-3+1x3-4:2 = ? ( )