Mrs. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.Find their present ages?​

Question

Mrs. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.Find their present ages?​

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Eden 4 weeks 2021-09-18T16:56:56+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-18T16:58:06+00:00

    Given : Mrs. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.

    To Find : Their present ages.

    ⠀⠀⠀⠀⠀__________________________

    ❍Let the present age of Nilu be “x” years.

    Therefore,the present age of Nilu’s mother = (x + 27) years.

    \\

    {\underline{\boldsymbol{\pink{According \ to \ the \ question \ :}}}}

    So,after 8 years,

    Nilu’s age = (x + 8),and Mrs Jain’s age = (x + 27 + 8) = (x + 35)years.

     :\implies{ \sf{\pink{x + 35 = 2(x + 8)}}}

    \\

    Expanding the brackets,We get

     :\implies{ \sf{\pink{x + 35 = 2x + 16}}}

    \\

    Transporing x to RHS and 16 to LHS,We get

     :\implies{ \sf{\pink{35-16=2x-x}}}

    \\

     :\implies{ \sf{\pink{x=19}}}

    \\

    So,The present age of Nilu = x = 19 years.And the present age of Nilu’s mother that is Mrs Jain = x + 27 = 19 + 27 = 46 years.

    0
    2021-09-18T16:58:15+00:00

    answer

    Step-by-step explanation:

    ǫsɪɴ :

    Mrs. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.Find their present ages?

    ________________________________

    ʀǫɪʀ sʟɪɴ :

    Daughter Age = x

    Neelu’s Age = 27 + x

    After 8 Years,

    Daughter Age = x + 8

    Neelu’s Age = 27+8+x

    = 35 + x

    2( x + 8) = 35 + x

    2x + 16 = 35 + x

    2x – x = 35 – 16

    x = 19

    Daughter present age = 19 Years

    Neelu’s Present Age = 27+ x

    = 27 + 19

    = 46 ʏᴇᴀʀs.

    ʜʀғʀ, ɴʟs ʀsɴ ɢ ɪs 46 ʏʀs.

    ________________________________

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