Mrs. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.Find their present ages?​

2 thoughts on “Mrs. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.Find their present ages?​”

1. Given : Mrs. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.

   To Find : Their present ages.

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   ❍Let the present age of Nilu be “x” years.

   Therefore,the present age of Nilu’s mother = (x + 27) years.

   [tex]\\[/tex]

   [tex]{\underline{\boldsymbol{\pink{According \ to \ the \ question \ :}}}}[/tex]

   So,after 8 years,

   Nilu’s age = (x + 8),and Mrs Jain’s age = (x + 27 + 8) = (x + 35)years.

   [tex] :\implies{ \sf{\pink{x + 35 = 2(x + 8)}}}[/tex]

   [tex]\\[/tex]

   Expanding the brackets,We get

   [tex] :\implies{ \sf{\pink{x + 35 = 2x + 16}}}[/tex]

   [tex]\\[/tex]

   Transporing x to RHS and 16 to LHS,We get

   [tex] :\implies{ \sf{\pink{35-16=2x-x}}}[/tex]

   [tex]\\[/tex]

   [tex] :\implies{ \sf{\pink{x=19}}}[/tex]

   [tex]\\[/tex]

   So,The present age of Nilu = x = 19 years.And the present age of Nilu’s mother that is Mrs Jain = x + 27 = 19 + 27 = 46 years.

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2. [tex]answer[/tex]

   Step-by-step explanation:

   ❒ ǫᴜᴇsᴛɪᴏɴ :

   Mrs. Jain is 27 years older than her daughter nilu.After 8 years she will be twice as old as Nilu.Find their present ages?

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   ❒ ʀᴇǫɪʀᴇᴅ sᴏʟᴜᴛɪᴏɴ :

   Daughter Age = x

   Neelu’s Age = 27 + x

   After 8 Years,

   Daughter Age = x + 8

   Neelu’s Age = 27+8+x

   = 35 + x

   2( x + 8) = 35 + x

   2x + 16 = 35 + x

   2x – x = 35 – 16

   x = 19

   Daughter present age = 19 Years

   Neelu’s Present Age = 27+ x

   = 27 + 19

   = 46 ʏᴇᴀʀs.

   ● ᴛʜᴇʀᴇғᴏʀᴇ, ɴᴇᴇʟᴜ‘s ᴘʀᴇsᴇɴᴛ ᴀɢᴇ ɪs 46 ʏᴇᴀʀs.

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