if 4.2 mole of oxygen is required in formation of potassium chlorate when react with KCL. calculate the mass of KCL and KCLO3 also

Question

if 4.2 mole of oxygen is required in formation of potassium chlorate when react with KCL. calculate the mass of KCL and KCLO3 also calculate volume of kcl​

in progress 0
Emery 2 months 2021-07-27T14:45:58+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-27T14:47:14+00:00

    Answer:

    Decomposition of KClO

    3

    takes place as:

    2KClO

    3

    (s)→2KCl(s)+3O

    2

    (g)

    2 mole of KClO

    3

    =3 mole of O

    2

    ∵ 3 mole O

    2

    formed by 2 mole KClO

    3

    ∴2.4 mole of O

    2

    will be formed by:

    (

    3

    2

    ×2.4) mol KClO

    3

    = 1.6 mole of KClO

    3

    .

    Mass of KClO

    3

    = Number of moles × Molar mass

    =1.6×122.5=196g

Leave an answer

Browse

9:3-3+1x3-4:2 = ? ( )