if 4.2 mole of oxygen is required in formation of potassium chlorate when react with KCL. calculate the mass of KCL and KCLO3 also

1 thought on “if 4.2 mole of oxygen is required in formation of potassium chlorate when react with KCL. calculate the mass of KCL and KCLO3 also”

1. Answer:

   Decomposition of KClO

   3

   takes place as:

   2KClO

   3

   (s)→2KCl(s)+3O

   2

   (g)

   2 mole of KClO

   3

   =3 mole of O

   2

   ∵ 3 mole O

   2

   formed by 2 mole KClO

   3

   ∴2.4 mole of O

   2

   will be formed by:

   (

   3

   2

   ×2.4) mol KClO

   3

   = 1.6 mole of KClO

   3

   .

   Mass of KClO

   3

   = Number of moles × Molar mass

   =1.6×122.5=196g

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