Find zeros of
the polynomial
 \sqrt{3x {}^{2} }   - 8x  + 4 \sqrt{3}

Question

Find zeros of
the polynomial
 \sqrt{3x {}^{2} }   - 8x  + 4 \sqrt{3}

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Rylee 2 years 2021-07-15T14:45:41+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-15T14:47:22+00:00

    Given Polynomial : √3x² – 8x + 4√3

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    Need to find : The Zeroes of the given polynomial.

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    \:\:❭❭ Finding out the zeroes of Given polynomial :

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    \:\:\:\:\:\:\:\:\::\:\Longrightarrow\:{\sf{\sqrt{3}}x^{2}\:-\:8x\:+\:4\sqrt{3}}

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    \:\:\:\:\:\:\:\:\:\::\:\Longrightarrow\:{\sf{\sqrt{3}}x^{2}\:-\:8x\:+\:4\sqrt{3}\:=\:0}

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    \:\:\:\:\:\::\:\Longrightarrow\:{\sf{\sqrt{3}}x^{2}\:-\:2x\:-\:6x\:+\:4\sqrt{3}}

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    \:\:\:\:\:\:\:\:\::\:\Longrightarrow\:{\sf{(\:\sqrt{3}x\:-\:2\:)\:(\:x\:-\:2\sqrt{3}\:)}}

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    \:\:\::\:\Longrightarrow\:{\underline{\boxed{\frak{\blue{x\:=\:{\dfrac{2}{\sqrt{3}}}\:or\:x\:=\:2\sqrt{3}}}}}}\:\bigstar

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    \:\therefore\:{\underline{\sf{Hence,\:the\:zeroes\:of\:the\:given\:polynomial\:are\:{\sf{\bf{\dfrac{2}{\sqrt{3}}\:or\:2\sqrt{3}}}}}}}.

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    \:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━

    {\mathsf{\mathbf{\pink{@ℐᴛᴢӇᴀᴘᴘʏҨᴜᴇᴇɴ࿐}}}}

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