Find zeros of
the polynomial
[tex] \sqrt{3x {}^{2} } – 8x + 4 \sqrt{3} [/tex]
​

1 thought on “Find zeros of<br />the polynomial<br />[tex] \sqrt{3x {}^{2} } – 8x + 4 \sqrt{3} [/tex]<br />​”

1. Given Polynomial : √3x² – 8x + 4√3

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   Need to find : The Zeroes of the given polynomial.

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   [tex]\:\:[/tex]❭❭ Finding out the zeroes of Given polynomial :

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   [tex]\:\:\:\:\:\:\:\:\::\:\Longrightarrow\:{\sf{\sqrt{3}}x^{2}\:-\:8x\:+\:4\sqrt{3}}[/tex]

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   [tex]\:\:\:\:\:\:\:\:\:\::\:\Longrightarrow\:{\sf{\sqrt{3}}x^{2}\:-\:8x\:+\:4\sqrt{3}\:=\:0}[/tex]

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   [tex]\:\:\:\:\:\::\:\Longrightarrow\:{\sf{\sqrt{3}}x^{2}\:-\:2x\:-\:6x\:+\:4\sqrt{3}}[/tex]

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   [tex]\:\:\:\:\:\:\:\:\::\:\Longrightarrow\:{\sf{(\:\sqrt{3}x\:-\:2\:)\:(\:x\:-\:2\sqrt{3}\:)}}[/tex]

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   [tex]\:\:\::\:\Longrightarrow\:{\underline{\boxed{\frak{\blue{x\:=\:{\dfrac{2}{\sqrt{3}}}\:or\:x\:=\:2\sqrt{3}}}}}}\:\bigstar[/tex]

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   [tex]\:\therefore\:{\underline{\sf{Hence,\:the\:zeroes\:of\:the\:given\:polynomial\:are\:{\sf{\bf{\dfrac{2}{\sqrt{3}}\:or\:2\sqrt{3}}}}}}}.[/tex]

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   [tex]\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━[/tex]

   [tex]{\mathsf{\mathbf{\pink{@ℐᴛᴢӇᴀᴘᴘʏҨᴜᴇᴇɴ࿐}}}}[/tex]

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