Answer: The natural numbers between 1 and 200 that are multiples of 5 are 5,10,15,195 We have a=5,d=10−5=5 and l=195 l=a+(n−1)d 195=5+(n−1)5 ⇒195−5=5(n−1) ⇒n−1=5190=36 ⇒n=36+1=37 terms ∴Sn=2n(a+l) S37=237(5+195) S37=237×200 S37=37×100=3700 ∴ Sum of all natural numbers between 1 and 200 which are multiples of 5 is 3700 Reply
Answer:
The natural numbers between 1 and 200 that are multiples of 5 are
5,10,15,195
We have a=5,d=10−5=5 and l=195
l=a+(n−1)d
195=5+(n−1)5
⇒195−5=5(n−1)
⇒n−1=5190=36
⇒n=36+1=37 terms
∴Sn=2n(a+l)
S37=237(5+195)
S37=237×200
S37=37×100=3700
∴ Sum of all natural numbers between 1 and 200 which are multiples of 5 is 3700