find the sum of all natural numbers b/w 1 and 200 which are multiples of 5

Question

Eloise · Answer

Answer:   The natural numbers between 1 and 200 that are multiples of 5 are       5,10,15,195      We have a=5,d=10−5=5 and l=195      l=a+(n−1)d      195=5+(n−1)5      ⇒195−5=5(n−1)      ⇒n−1=5190=36      ⇒n=36+1=37 terms      ∴Sn=2n(a+l)      S37=237(5+195)      S37=237×200      S37=37×100=3700      ∴ Sum of all natural numbers between 1 and 200 which are multiples of 5 is 3700

Margaret

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