Find the quadratic polynomial with zeroes 2 and

−1

3​

Question

Find the quadratic polynomial with zeroes 2 and

−1

3​

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Nevaeh 1 month 2021-08-16T06:37:26+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-08-16T06:39:25+00:00

    Answer:

    The quadratic polynomial will be = (1/3)(3x^2–5x—2).

    Step-by-step explanation:

    • Let be quadratic polynomial be ax ^2  +bx +c and its zeroes be α and β

    In our case ,α =2 and β = (-1/3)

    • Sum of zeroes= α+β = 2 + (-1/3) = 2 – ( 1/3 )= (6–1)/3 =5/3
    • Product of zeroes= αβ= 2*(-1/3)= -2/3
    • The quadratic polynomial with the variable x :

    =x^2- (sum of zeroes)x+ (product of zeroes)

    =x^2- (5/3)x + (-2/3)

    =(3x^2 – 5x -2)/3

    =(1/3)(3x^2–5x—2)

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