Answer: The quadratic polynomial will be = (1/3)(3x^2–5x—2). Step-by-step explanation: Let be quadratic polynomial be ax ^2 +bx +c and its zeroes be α and β In our case ,α =2 and β = (-1/3) Sum of zeroes= α+β = 2 + (-1/3) = 2 – ( 1/3 )= (6–1)/3 =5/3 Product of zeroes= αβ= 2*(-1/3)= -2/3 The quadratic polynomial with the variable x : =x^2- (sum of zeroes)x+ (product of zeroes) =x^2- (5/3)x + (-2/3) =(3x^2 – 5x -2)/3 =(1/3)(3x^2–5x—2) Reply
Answer:
The quadratic polynomial will be = (1/3)(3x^2–5x—2).
Step-by-step explanation:
In our case ,α =2 and β = (-1/3)
=x^2- (sum of zeroes)x+ (product of zeroes)
=x^2- (5/3)x + (-2/3)
=(3x^2 – 5x -2)/3
=(1/3)(3x^2–5x—2)