Find the greatest number of 4-digit exactly divisible by 12, 16, 24,

28 and 36

Question

Find the greatest number of 4-digit exactly divisible by 12, 16, 24,

28 and 36

in progress 0
Mackenzie 2 years 2021-07-17T14:27:51+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-17T14:29:30+00:00

    Step-by-step explanation:

    First of all we need to find the L.C.M. (12,16,24,28,36)

    12=2*2*3

    16=2*2*2*2

    24=2*2*2*3

    28=2*2*7

    36=2*2*3*3

    Therefore l.c.m

    2*2*3*7*3*2*2=1008

    Now greatest no of 4 digit is 9999

    Let us divide 9999 by 1008

    Then we will have 927 as reminder

    So if we subtract 927 from 9999 then the result must be divisible by 1008 i.e the LCM of the given no.s i.e each of the no.s.

    So our number will be 9999–927=9072..

    ∴The greatest 4 digit number exactly divisible by 12, 16, 24, 28 and 36

    =9×1008=9072

Leave an answer

Browse

9:3-3+1x3-4:2 = ? ( )