other, find the value of a.7. Find a quadratic polynomial whose zeros are 2 and -5. About the author Mackenzie
Answer: x^2 + 3x – 10 Step-by-step explanation: alpha = 2 , beta = -5 sum of zeroes = alpha + beta = 2 + (-5) = 2-5 = -3 product of zeroes = alpha*beta = 2*(-5) = -10 substituting the values in the formula [x^2 – ( alpha + beta )x + alpha*beta ] we get [ x^2 – ( -3)x + (-10)] x^2 +3x – 10 Reply
Answer:
x^2 + 3x – 10
Step-by-step explanation:
alpha = 2 , beta = -5
sum of zeroes = alpha + beta
= 2 + (-5)
= 2-5
= -3
product of zeroes = alpha*beta
= 2*(-5)
= -10
substituting the values in the formula [x^2 – ( alpha + beta )x + alpha*beta ] we get
[ x^2 – ( -3)x + (-10)]
x^2 +3x – 10