father age is 3 time the sum of the ages two children after 5 years his age will be twice the sum of ages of two children find the agebof father
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Answer:
Let the present age of father be x years
And, the present age of two children be y years
⠀⠀⠀⠀⠀⠀⠀⠀According to the Given Condition
Father age is 3 time the sum of the age of two children .
[tex]:\implies[/tex] x = 3y ––––––––––(i)
Again ,
After 5 years his age will be twice the sum of ages of two children .
[tex]:\implies[/tex] x+5 = 2(y+10)
[tex]:\implies[/tex] x+5 = 2y + 20
[tex]:\implies[/tex] x -2y = 15 ––––––––(ii)
Now, substitute the value of x = 3y in equation (ii) we get
[tex]:\implies[/tex] 3y -2y = 15
[tex]:\implies[/tex] y = 15
Putting the value of y = 15 in equation (i) we get
[tex]:\implies[/tex] x = 3×15
[tex]:\implies[/tex] x = 45
Given :-
Father age is 3 time the sum of the ages two children after 5 years his age will be twice the sum of ages of two children
To Find :-
Age of father
Solution :-
Let age of father be x
Age of two children be y
x = 3 × y
x = 3y
After 5 years
Age of father = x + 5
Age of two sons = y + 5 + 5 = y + 10
Now
x + 5 = 2(y + 10)
x + 5 = 2y + 20
x – 2y = 20 – 5
x – 2y = 15
3y – 2y = 15
y = 15
x – 2(15) = 15
x – 30 = 15
x = 30 + 15
x = 45
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