construct a quadrilateral ABCD. in which AB=BC=AD=5cm,zAC=7cm and BD=6cm​

Question

construct a quadrilateral ABCD. in which AB=BC=AD=5cm,zAC=7cm and BD=6cm​

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Eloise 3 months 2021-07-21T01:50:39+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-21T01:51:43+00:00

    Step-by-step explanation:

    ⇒ With A as a center and radius AC = 8cm, draw an arc intersecting the previous arc at point C. ⇒ Again take B as a center and radius BD = 7cm, draw an arc. ⇒ With C as a center and radius CD = 7cm, draw an arc intersecting the previous arc at point D. ⇒ Join AC, BC, BD, CD and AD.

    0
    2021-07-21T01:52:28+00:00

    \huge \fbox \green{❤Answer:}

    Steps for construction :

    • Draw a loine segment AB =5cm
    • From A as centre, draw an arc above AB of radius 5cm.
    • from point B as crentre draw an arc of 6 cm

    ㅤㅤㅤwhich cuts the previous arc at D.

    • from point A as centre draw an arc of radiu s 7cm.
    • from point B as centre draw an arc of radiu

    ㅤㅤㅤs 5 cm which cuts the previous arc ㅤㅤㅤat C

    • Join AC , BD and CD.
    • Thus ABCD is required quadrilateral

    Look at the pic

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