2 thoughts on “construct a quadrilateral ABCD. in which AB=BC=AD=5cm,zAC=7cm and BD=6cm”
Step-by-step explanation:
⇒ With A as a center and radius AC = 8cm, draw an arc intersecting the previous arc at point C. ⇒ Again take B as a center and radius BD = 7cm, draw an arc. ⇒ With C as a center and radius CD = 7cm, draw an arc intersecting the previous arc at point D. ⇒ Join AC, BC, BD, CD and AD.
Step-by-step explanation:
⇒ With A as a center and radius AC = 8cm, draw an arc intersecting the previous arc at point C. ⇒ Again take B as a center and radius BD = 7cm, draw an arc. ⇒ With C as a center and radius CD = 7cm, draw an arc intersecting the previous arc at point D. ⇒ Join AC, BC, BD, CD and AD.
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Steps for construction :
ㅤㅤㅤwhich cuts the previous arc at D.
ㅤㅤㅤs 5 cm which cuts the previous arc ㅤㅤㅤat C
Look at the pic
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