BC=12cm BD =3cm area of triangle ABC=80sq.cm. Find the area of triangle ADC and the triangle ABD​

Question

BC=12cm BD =3cm area of triangle ABC=80sq.cm. Find the area of triangle ADC and the triangle ABD​

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Bella 1 month 2021-08-06T08:16:36+00:00 2 Answers 0 views 0

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    0
    2021-08-06T08:17:44+00:00

    Step-by-step explanation:

    आ हहWhat Should Be Added to (-7)/12 to Get 3/8? – Mathematics

    ∴ – 7 12 + x = 3 8.

    ⇒ x = 3 8 – – 7 12.

    = 9 24 + 14 24.

    = 9 + 14 24 = 23 24.

    0
    2021-08-06T08:17:59+00:00

    Answer:

    The area of Δ ADC= 60 square cm.

    Explanation:

    Since we have given that

    BC=12

    BD=3

    DC=BC-BD=12-3=9

    So, BD:DC=3:9=1:3

    So, we can let

    BD=x and DC=3x

    Now,

    \frac{\Delta ABD}{\Delta ADC}=\frac{\frac{1}{2}\times x\times h}{\frac{1}{2}\times 3x\times h}=\frac{1}{3}

    ΔADC

    ΔABD

    =

    2

    1

    ×3x×h

    2

    1

    ×x×h

    =

    3

    1

    So,

    \begin{gathered}3ABD=ADC\\\end{gathered}

    3ABD=ADC

    Now,

    \begin{gathered}\Delta ABD+\Delta ADC=\Delta ABC\\\\\frac{\Delta ADC}{3}+\Delta ADC=\Delta ABC\\\\\frac{4\Delta ADC}{3}=80\\\\\Delta ADC=60\text{ square cm}\end{gathered}

    ΔABD+ΔADC=ΔABC

    3

    ΔADC

    +ΔADC=ΔABC

    3

    4ΔADC

    =80

    ΔADC=60 square cm

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