BC=12cm BD =3cm area of triangle ABC=80sq.cm. Find the area of triangle ADC and the triangle ABD​

2 thoughts on “BC=12cm BD =3cm area of triangle ABC=80sq.cm. Find the area of triangle ADC and the triangle ABD​”

1. Step-by-step explanation:

   आ हहWhat Should Be Added to (-7)/12 to Get 3/8? – Mathematics

   ∴ – 7 12 + x = 3 8.

   ⇒ x = 3 8 – – 7 12.

   = 9 24 + 14 24.

   = 9 + 14 24 = 23 24.

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2. Answer:

   The area of Δ ADC= 60 square cm.

   Explanation:

   Since we have given that

   BC=12

   BD=3

   DC=BC-BD=12-3=9

   So, BD:DC=3:9=1:3

   So, we can let

   BD=x and DC=3x

   Now,

   \frac{\Delta ABD}{\Delta ADC}=\frac{\frac{1}{2}\times x\times h}{\frac{1}{2}\times 3x\times h}=\frac{1}{3}

   ΔADC

   ΔABD

   =

   2

   1

   ×3x×h

   2

   1

   ×x×h

   =

   3

   1

   So,

   \begin{gathered}3ABD=ADC\\\end{gathered}

   3ABD=ADC

   Now,

   \begin{gathered}\Delta ABD+\Delta ADC=\Delta ABC\\\\\frac{\Delta ADC}{3}+\Delta ADC=\Delta ABC\\\\\frac{4\Delta ADC}{3}=80\\\\\Delta ADC=60\text{ square cm}\end{gathered}

   ΔABD+ΔADC=ΔABC

   3

   ΔADC

   +ΔADC=ΔABC

   3

   4ΔADC

   =80

   ΔADC=60 square cm

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