## ABCD is a quadrilateral in which angle BAD =105, angel BCD =150 and BC= 13cm . find AC? please solve this question

Question

ABCD is a quadrilateral in which angle BAD =105, angel BCD =150 and BC= 13cm . find AC? please solve this question

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Mathematics
1 month
2021-08-16T03:29:33+00:00
2021-08-16T03:29:33+00:00 1 Answers
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## Answers ( )

Answer:(i) Join BD

Now, ABCD is a cyclic quadrilateral

∴ ∠BAD + ∠BCD = 180° (Opposite angles of a cyclic quadrilateral)

=> ∠BAD + 150° = 180°

=> ∠BAD = 180° – 150° = 30°

(ii) ∠ABD = 90° (Angle in a semi-circle)

Now, In △ABD, we have

∠ABD + ∠BAD + ∠ADB = 180°

90° + 30° + ∠ADB = 180°

=> ∠ADB = 180° – 120° = 60°