11. The values of two resistors are R, = (6 0.3) k12
and R2 = (10 + 0.2) k2. The percentage error in
the equivalent resi

Question

11. The values of two resistors are R, = (6 0.3) k12
and R2 = (10 + 0.2) k2. The percentage error in
the equivalent resistance when they are connected
in parallel is
(1) 5.125%
(2) 2%
(3) 3.875%
(4) 7%

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Eloise 2 months 2021-08-01T10:35:35+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-01T10:36:41+00:00

    Answer:

    When the two resistors are connected in parallel, the equivalent resistance will be

    R

    P

    =

    R

    1

    +R

    2

    R

    1

    R

    2

    Differentiating both sides ,

    R

    P

    ΔR

    P

    =

    R

    1

    ΔR

    1

    +

    R

    2

    ΔR

    2

    +

    R

    1

    +R

    2

    Δ(R

    1

    +R

    2

    )

    R

    P

    ΔR

    P

    =

    6

    0.3

    +

    10

    0.2

    +

    16

    0.3+0.2

    =0.05+0.02+0.03125=0.10125

    % error =

    R

    P

    ΔR

    P

    ×100=0.10125×100=10.125%

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    0
    2021-08-01T10:37:28+00:00

    Explanation:

    I am sorry I don’t no this is

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