11. The values of two resistors are R, = (6 0.3) k12and R2 = (10 + 0.2) k2. The percentage error inthe equivalent resistance when they are connectedin parallel is(1) 5.125%(2) 2%(3) 3.875%(4) 7% About the author Eloise
Answer: When the two resistors are connected in parallel, the equivalent resistance will be R P = R 1 +R 2 R 1 R 2 Differentiating both sides , R P ΔR P = R 1 ΔR 1 + R 2 ΔR 2 + R 1 +R 2 Δ(R 1 +R 2 ) R P ΔR P = 6 0.3 + 10 0.2 + 16 0.3+0.2 =0.05+0.02+0.03125=0.10125 % error = R P ΔR P ×100=0.10125×100=10.125% mark me as Brainlist✌✌ Reply
Answer:
When the two resistors are connected in parallel, the equivalent resistance will be
R
P
=
R
1
+R
2
R
1
R
2
Differentiating both sides ,
R
P
ΔR
P
=
R
1
ΔR
1
+
R
2
ΔR
2
+
R
1
+R
2
Δ(R
1
+R
2
)
R
P
ΔR
P
=
6
0.3
+
10
0.2
+
16
0.3+0.2
=0.05+0.02+0.03125=0.10125
% error =
R
P
ΔR
P
×100=0.10125×100=10.125%
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Explanation:
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