10. Write the smallest number which when divided by 30, 45 and 60 leaves remainder 8 in each case,
Question
10. Write the smallest number which when divided by 30, 45 and 60 leaves remainder 8 in each case,
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Mathematics
2 years
2021-06-22T17:32:13+00:00
2021-06-22T17:32:13+00:00 1 Answers
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Step-by-step explanation:
first find factor of all numbers by LCM
30=3*2*5
45=3*3*5
60=3*2*2*5
now HCF is 3*5=15
And LCM is 2*3*2*2*15=360
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