10. Write the smallest number which when divided by 30, 45 and 60 leaves remainder 8 in each case,​

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10. Write the smallest number which when divided by 30, 45 and 60 leaves remainder 8 in each case,​

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Emma 2 years 2021-06-22T17:32:13+00:00 1 Answers 0 views 0

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    2021-06-22T17:33:59+00:00

    Step-by-step explanation:

    first find factor of all numbers by LCM

    30=3*2*5

    45=3*3*5

    60=3*2*2*5

    now HCF is 3*5=15

    And LCM is 2*3*2*2*15=360

    • now 360 is the number when divide by 30,45 and 60 leaves remainder 8.

    please check this answer and give brainlist

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