10. Write the smallest number which when divided by 30, 45 and 60 leaves remainder 8 in each case,​

1 thought on “10. Write the smallest number which when divided by 30, 45 and 60 leaves remainder 8 in each case,​”

1. Step-by-step explanation:

   first find factor of all numbers by LCM

   30=3*2*5

   45=3*3*5

   60=3*2*2*5

   now HCF is 3*5=15

   And LCM is 2*3*2*2*15=360

   • now 360 is the number when divide by 30,45 and 60 leaves remainder 8.

   please check this answer and give brainlist

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