Question :_________ If the sum of the zeroes of the polynomial p(x) = (k2 – 14) x2 – 2x – 12 is 1,➡️ then find the value of k ? ⚠️❌Don’t Spam pleech ❌⚠️ About the author Liliana
Answer: The given polynomial is (k²-14)x²-2x-12 The sum of zeros of a quadratic equation is -b/a. Hence, the sum of the zeros of the given quadratic is -(-2)/(k²-14) 2/(k²-14) Now, from the given directions, this expression should be equal to 1. 2/(k²-14) = 1 k²-14 = 2 k² = 16 k = √±4 hi sis good evening hope u are fine siso. aapne medicine le li na..XD Reply
Answer:
The given polynomial is (k²-14)x²-2x-12
The sum of zeros of a quadratic equation is -b/a.
Hence, the sum of the zeros of the given quadratic is
-(-2)/(k²-14)
2/(k²-14)
Now, from the given directions, this expression should be equal to 1.
2/(k²-14) = 1
k²-14 = 2
k² = 16
k = ñ4
hi sis
good evening
hope u are fine siso.
aapne medicine le li na..XD
Answer:
sum of zeroes – -b/a
1 = 2/k2-14
k2 – 14 = 2
k2 = 16
k = 4