Q. A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears a). a number divisible by 2 or 3.
2 thoughts on “Q. A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that”
[tex]\huge \bf \red {Aɴsᴡᴇʀ}[/tex]
The perfect square numbers between 1 to 90 are 1,4,9,16,25,36,49,64,81 which are 9 in number. So the possible outcome of choosing one disc at random from the box, is 90C1
The perfect square numbers between 1 to 90 are 1,4,9,16,25,36,49,64,81 which are 9 in number. So the possible outcome of choosing one disc at random from the box, is 90C1 . Thus the possible outcome of choosing one disc and it bears a perfect square number, is 9C1.
[tex]\huge \bf \red {Aɴsᴡᴇʀ}[/tex]
The perfect square numbers between 1 to 90 are 1,4,9,16,25,36,49,64,81 which are 9 in number. So the possible outcome of choosing one disc at random from the box, is 90C1
Answer:
The perfect square numbers between 1 to 90 are 1,4,9,16,25,36,49,64,81 which are 9 in number. So the possible outcome of choosing one disc at random from the box, is 90C1 . Thus the possible outcome of choosing one disc and it bears a perfect square number, is 9C1.