Prove that : tan theta + tan π – theta + cot ( π/2 + theta ) – tan ( 2π-theta ) = 0 Please help me. About the author Emery
Answer: L.H.S= tanθ + [- tanθ] – tanθ + tanθ L.H.S = tanθ – tanθ – tanθ + tanθ L.H.S = 0 = R.H.S Hope this helps ya! Reply
Answer:
L.H.S= tanθ + [- tanθ] – tanθ + tanθ
L.H.S = tanθ – tanθ – tanθ + tanθ
L.H.S = 0 = R.H.S
Hope this helps ya!
Answer:
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