Prove that ∆RSV ≅ ∆RKV, if RS = RK = 7 cm and RV = 5 cm and RV is perpendicular to SK.​

2 thoughts on “Prove that ∆RSV ≅ ∆RKV, if RS = RK = 7 cm and RV = 5 cm and RV is perpendicular to SK.​”

1. Answer:

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2. Step-by-step explanation:

   LengthofDE=3.5cm

   Step-by-step explanation:

   Midpoint Theorem:

   The line segment joining the midpoints of two sides of a triangle is parallel to the third side and also half of it .

   Given :

   In ∆ABC , AB = 5 cm ,

   BC = 8 cm,

   and CA = 7 cm ,

   D and E are respectively the midpoints of AB and BC .

   DE = \frac{1}{2} \times ACDE=21×AC

   = \frac{1}{2} \times 7=21×7

   = 3.5 \:cm=3.5cm

   Therefore.,

   \red { Length \: of \: DE } \green {= 3.5 \:cm }LengthofDE=3.5cm

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