Prove that : “In right angle triangle, the square of hypotenus is equal to

the sum of the sequares of remaing two sides.”

# Prove that : “In right angle triangle, the square of hypotenus is equal to

### 1 thought on “Prove that : “In right angle triangle, the square of hypotenus is equal to<br />the sum of the sequares of remaing two sides.””

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According to Pythagoras rule(H)²=(B)²+(P)².

Just take an example a right angle triangle have perpencular or P as 8cm and base or B as 6 cm so what will be the hypotenuse.

By using Pythagoras rule i.e.(H)²=(B)²+(P)²

it’s (H)²=(8)²+(6)²

or(H)²= 64+36

or (H)²= √100

or H=10.

Thus it proves that in right angle triangle the square of hypotenuse is equal to square of perpendicular or P and base or B or the remaining two sides.