Prove that : “In right angle triangle, the square of hypotenus is equal to
the sum of the sequares of remaing two sides.”​

Prove that : “In right angle triangle, the square of hypotenus is equal to
the sum of the sequares of remaing two sides.”​

1 thought on “Prove that : “In right angle triangle, the square of hypotenus is equal to<br />the sum of the sequares of remaing two sides.”​”

  1. According to Pythagoras rule(H)²=(B)²+(P)².

    Just take an example a right angle triangle have perpencular or P as 8cm and base or B as 6 cm so what will be the hypotenuse.

    By using Pythagoras rule i.e.(H)²=(B)²+(P)²

    it’s (H)²=(8)²+(6)²

    or(H)²= 64+36

    or (H)²= √100

    or H=10.

    Thus it proves that in right angle triangle the square of hypotenuse is equal to square of perpendicular or P and base or B or the remaining two sides.

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