Prove that the angle in a semicircle is a right angle.
∴∠AOB=2∠APB (∠AOB is the subtended at center which is equal to 180∘ and ∠APB is the angle made at any point on the circle.) … Also, Angle subtended by any straight line when moved from one point to another point forming an arc on the line is 180°….
Answer:
To prove : ∠APB=90
0
∵ We know angle subtended by an arc at centre is double the angle subtended at any point or circumference.
⇒ Angle subtended by arc AB at O= Double the angle subtended at P
⇒∠AOB=2∠APB
∵AOB is a straight line.
⇒∠AOB=180
0
⇒2∠APB=180
0
⇒∠APB=90
0
∴ Angle subtended by arc AB or semi circle is 90
0
.
Step-by-step explanation:
Prove that the angle in a semicircle is a right angle.
∴∠AOB=2∠APB (∠AOB is the subtended at center which is equal to 180∘ and ∠APB is the angle made at any point on the circle.) … Also, Angle subtended by any straight line when moved from one point to another point forming an arc on the line is 180°….
this is your answer..
mark it as BRAINLIEST..