Proof that 3 – \sqrt{8} is irrational.

→Need quality answer.​

Proof that 3 – \sqrt{8} is irrational.

→Need quality answer.​

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2 thoughts on “Proof that 3 – \sqrt{8} is irrational.<br /><br />→Need quality answer.​”

  1. Step-by-step explanation:

    Given :

    3-√8

    To find :

    Prove that 3-√8 is an irrational number ?

    Solution :

    Given that :

    3-√8

    It can be written as 3-√(2×2×2)

    => 3 – 2√2

    Let us assume that

    3 – 2√2 is a rational number

    It must be in the form of p/q , where p and q are integers and q ≠ 0

    Let 3-2√2 = a/b

    Where a and b are co-primes

    => -2√2 = (a/b) -3

    => 2√2 = 3-(a/b)

    => 2√2 = (3b-a)/b

    => √2 = (3b-a)/(2×b)

    => √2 = (3b-a)/2b

    =>√2 is in the form of p/q

    => √2 is a rational number

    But We know that

    => √2 is not a rational number.

    => √2 is an irrational number

    This contradicts to our assumption that (3-√8) is a rational number.

    3-√8 is not a rational number.

    3-√8 is an irrational number.

    Hence, Proved.

    Answer:

    3-√8 is an irrational number.

    Note :-

    3 is a rational number

    √8 is an irrational number

    The difference between the rational and irrational is also an irrational number.

    3-√8 is an irrational number.

    Used Method :

    • Method of Contradiction or Indirect method

    Points to know :

    • The numbers are in the form of p/q ,where p and q are integers and q≠0 called rational numbers. They are denoted by Q.
    • The numbers are not in the form of p/q ,where p and q are integers and q≠0 called irrational numbers. They are denoted by Q’ or S.
    • If q is the rational number and s is the irrational number then
    • q+s is an irrational number.
    • q-s is an irrational number.
    • q×s is an irrational number.
    • q/s is an irrational number.

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  2. Answer:

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    Step-by-step explanation:

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    Reply

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