probability that the bomb will hit the target is 0.8 find the probability that out of ten bombs dropped ,excetly two will miss the

2 thoughts on “probability that the bomb will hit the target is 0.8 find the probability that out of ten bombs dropped ,excetly two will miss the”

1. [tex]\large\underline{\sf{Solution-}}[/tex]

   We know,

   By Binomial Distribution,

   [tex] \boxed{ \bf \: P(r) = \:^n C_r {p}^{r} {q}^{n – r} }[/tex]

   where,

   • n = number of trials

   • p = probability of success

   • q = probability of failure

   • r = random variable whom success is desired.

   and

   • p + q = 1.

   Let’s solve the problem now!!

   Here, given that

   • Number of bombs dropped, n = 10.

   • Probability that bomb hit the target, p = 0.8

   So,

   • Probability that bimb will not hit target, q = 1 – 0.8 = 0.2

   Now,

   We have to find the probability exactly 2 bombs will miss the target.

   [tex]\bf :\longmapsto\:P(exactly \: 2 \: bombs \: miss \: the \: target)[/tex]

   [tex] \: \: \bf \: = \: P(exactly \: 8 \: bombs \: hit \: the \: target)[/tex]

   [tex] \: \: = \sf \: \:^{10} C_8 \: \times {(0.8)}^{8} \times {(0.2)}^{2} [/tex]

   [tex] \: \: = \sf \: \dfrac{10 \times 9}{2 \times 1} \times {\bigg( \dfrac{8}{10} \bigg) }^{8} \times {\bigg( \dfrac{2}{10} \bigg) }^{2} [/tex]

   [tex] \: \: = \sf \: 45 \times {\bigg(\dfrac{4}{5} \bigg) }^{8} \times {\bigg( \dfrac{1}{5} \bigg) }^{2} [/tex]

   [tex] \: \: = \sf \: 45 \times \dfrac{ {4}^{8} }{ {5}^{8} } \times \dfrac{1}{ {5}^{2} } [/tex]

   [tex] \: \: = \sf \: \dfrac{9 \times {2}^{16} }{ {5}^{9} } [/tex]

   Additional Information :-

   If the following conditions are satisfied, then X has a binomial distribution with parameters n and p, represented as B(n,p).

   • 1. The number of observations n is fixed.

   • 2. Each observation is independent.

   • 3. Each observation represents one of two outcomes (succes, p or failure, q).

   • 4. The probability of “success” p is the same for each outcome.

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2. Answer:

   Answer:Answer is 9.2

   Answer:Answer is 9.2Step-by-step explanation:

   Answer:Answer is 9.2Step-by-step explanation:Probability that the bomb will hit the target is 0.8

   Answer:Answer is 9.2Step-by-step explanation:Probability that the bomb will hit the target is 0.8 n(s)= 0.8

   Answer:Answer is 9.2Step-by-step explanation:Probability that the bomb will hit the target is 0.8 n(s)= 0.8Find the probability that out of ten bombs

   Answer:Answer is 9.2Step-by-step explanation:Probability that the bomb will hit the target is 0.8 n(s)= 0.8Find the probability that out of ten bombs n(e)= 10

   Answer:Answer is 9.2Step-by-step explanation:Probability that the bomb will hit the target is 0.8 n(s)= 0.8Find the probability that out of ten bombs n(e)= 10 P(e) = n(e)/n(s)

   Answer:Answer is 9.2Step-by-step explanation:Probability that the bomb will hit the target is 0.8 n(s)= 0.8Find the probability that out of ten bombs n(e)= 10 P(e) = n(e)/n(s) 10 – 0.8

   Answer:Answer is 9.2Step-by-step explanation:Probability that the bomb will hit the target is 0.8 n(s)= 0.8Find the probability that out of ten bombs n(e)= 10 P(e) = n(e)/n(s) 10 – 0.8 Answer is 9.2

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