1 thought on “One of the exterior angles of a triangle is 100″. Find the values of interior opposite<br />ongles at they are in the ratio<br />l”

•Exterior angle is the sum of the two interior opposite angles A) 1x + 1x = 100 2x = 100 x = 100/2 x = 50 Angles are 50 and 50 ( 1x = 1*50) B) 3x + 2x = 100 5x = 100/5 x = 20 Angles are 60 (3*20) and 40 (2*20) C) 1x + 3x = 100 4x = 100 x = 100/4 x = 25 Angles are 25 and 75

•Exterior angle is the sum of the two interior opposite angles

A) 1x + 1x = 100

2x = 100

x = 100/2

x = 50

Angles are 50 and 50 ( 1x = 1*50)

B) 3x + 2x = 100

5x = 100/5

x = 20

Angles are 60 (3*20) and 40 (2*20)

C) 1x + 3x = 100

4x = 100

x = 100/4

x = 25

Angles are 25 and 75