1 thought on “One of the exterior angles of a triangle is 100″. Find the values of interior opposite<br />ongles at they are in the ratio<br />l”
•Exterior angle is the sum of the two interior opposite angles A) 1x + 1x = 100 2x = 100 x = 100/2 x = 50 Angles are 50 and 50 ( 1x = 1*50) B) 3x + 2x = 100 5x = 100/5 x = 20 Angles are 60 (3*20) and 40 (2*20) C) 1x + 3x = 100 4x = 100 x = 100/4 x = 25 Angles are 25 and 75
•Exterior angle is the sum of the two interior opposite angles
A) 1x + 1x = 100
2x = 100
x = 100/2
x = 50
Angles are 50 and 50 ( 1x = 1*50)
B) 3x + 2x = 100
5x = 100/5
x = 20
Angles are 60 (3*20) and 40 (2*20)
C) 1x + 3x = 100
4x = 100
x = 100/4
x = 25
Angles are 25 and 75