one angle of a quadrilateral is 150 and 3 angles are equal. find the measures of the other three angles? About the author Ava
Answer: 70°,70°,70° Let \: the \: each \: equal \: angle \: be \: ‘x’.Lettheeachequalanglebe ′ x ′ . Sum of all angles of quadrilateral is 360° ⇒ 150 + x + x + x = 360⇒150+x+x+x=360 ⇒ 150 + 3x = 360⇒150+3x=360 ⇒ 3x = 360 – 150⇒3x=360−150 ⇒ 3x = 210⇒3x=210 ⇒ x = 210/3⇒x=210/3 ⇒ x = 70°⇒x=70° Value of each equal angle is 70 °. Reply
Answer: [tex]70°, 70°, 70°[/tex] [tex]Let \: the \: each \: equal \: angle \: be \: ‘x’.[/tex] Sum of all angles of quadrilateral is 360° [tex]⇒ 150 + x + x + x = 360 [/tex] [tex]⇒ 150 + 3x = 360[/tex] [tex]⇒ 3x = 360 – 150 [/tex] [tex]⇒ 3x = 210 [/tex] [tex]⇒ x = 210/3 [/tex] [tex]⇒ x = 70°[/tex] [tex]Value \: of \: each \: equal \: angle \: is \: 70[/tex] °. Reply
Answer:
70°,70°,70°
Let \: the \: each \: equal \: angle \: be \: ‘x’.Lettheeachequalanglebe
′
x
′
.
Sum of all angles of quadrilateral is 360°
⇒ 150 + x + x + x = 360⇒150+x+x+x=360
⇒ 150 + 3x = 360⇒150+3x=360
⇒ 3x = 360 – 150⇒3x=360−150
⇒ 3x = 210⇒3x=210
⇒ x = 210/3⇒x=210/3
⇒ x = 70°⇒x=70°
Value of each equal angle is 70
°.
Answer:
[tex]70°, 70°, 70°[/tex]
[tex]Let \: the \: each \: equal \: angle \: be \: ‘x’.[/tex]
Sum of all angles of quadrilateral is 360°
[tex]⇒ 150 + x + x + x = 360 [/tex]
[tex]⇒ 150 + 3x = 360[/tex]
[tex]⇒ 3x = 360 – 150 [/tex]
[tex]⇒ 3x = 210 [/tex]
[tex]⇒ x = 210/3 [/tex]
[tex]⇒ x = 70°[/tex]
[tex]Value \: of \: each \: equal \: angle \: is \: 70[/tex]
°.