onal numbers that lie betwee
(ii)
4 2
5 ‘ 3
7 -5​

1 thought on “onal numbers that lie betwee<br />(ii)<br />4 2<br />5 ‘ 3<br />7 -5​”

1. Answer:

   In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)

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