om the given data
0-20 20-40 40-60 60-80
15
р
18 10
eservations of the data are
5
of mode is 52

om the given data
0-20 20-40 40-60 60-80
15
р
18 10
eservations of the data are
5
of mode is 52. Then find the value of p’.​

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Hadley

1 thought on “om the given data<br />0-20 20-40 40-60 60-80<br />15<br />р<br />18 10<br />eservations of the data are<br />5<br />of mode is 52”

  1. Answer:

    Class = 0-20, 20-40, 40-60, 60-80, 80-100

    Frequency = 15, 6, 18, 10, 5

    The maximum class frequency is 18 and the class corresponding to this frequency is 40-60.

    So, the modal class is 40-60.

    Here, lower limit of modal class l= 40

    class size h= 20

    Frequency of the modal class f_{1}=18f

    1

    =18

    Frequency of class preceding the modal class f_{0}=6f

    0

    =6

    Frequency of class succeeding the modal class f_{2}=10f

    2

    =10

    We need to calculate the mode

    Using formula of mode

    Mode =l+(\dfrac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}})\times hMode=l+(

    2f

    1

    −f

    0

    −f

    2

    f

    1

    −f

    0

    )×h

    Put the value into the formula

    Mode=40+(\dfrac{18-6}{2\times18-6-10})\times20Mode=40+(

    2×18−6−10

    18−6

    )×20

    Mode=52Mode=52

    Hence, The mode is 52.

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