Object is placed at a distance of 4 cm from focus of concave mirror. Then image is formed at a distance of 16 cm from the focus on same side. What is the focallength of mirror ? About the author Amelia
Answer: 1/f = 1/u + 1/v here u = f+4, and v = f+16 1/f = 1/(f+4) + 1/(f+16) 1/f = (f+16+f+4)/((f+4)(f+16)) simplifying it, we get, f² = 64 f = √64 = 8 f = 8cm. Step-by-step explanation: Hope it helps. Mark as brainliest if it was helpful. Thank you. Reply
Answer:
1/f = 1/u + 1/v
here u = f+4, and v = f+16
1/f = 1/(f+4) + 1/(f+16)
1/f = (f+16+f+4)/((f+4)(f+16))
simplifying it, we get,
f² = 64
f = √64 = 8
f = 8cm.
Step-by-step explanation:
Hope it helps. Mark as brainliest if it was helpful. Thank you.