o solve the equation by elimination
(1) 2x+y=4
3x +2y = 6​

o solve the equation by elimination
(1) 2x+y=4
3x +2y = 6​

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2 thoughts on “o solve the equation by elimination<br />(1) 2x+y=4<br />3x +2y = 6​”

  1. [tex]{\boxed{\underline{\tt{\orange{Required \: \: answer:-}}}}}[/tex]

    ★GIVEN:-

    Two Equations:-

    • 2x + y = 4
    • 3x + 2y = 6

    ★SOLVED USING:-

    • Elimination Method

    ★SOLUTION:-

    [tex] : \longrightarrow \displaystyle \rm{2x + y = 4 } \\ \\ : \longrightarrow \displaystyle \rm{y = 4 – 2x….(1.)} [/tex]

    Now,

    [tex] : \longrightarrow \displaystyle \rm{3x + 2y = 6 } \\ \\ \sf{put \: the \: value \: of \: y \: from \: (1.) \: into \: this \: equation} \\ \\ : \longrightarrow \displaystyle \rm{3x + 2(4 – 2x) = 6} \\ \\ : \longrightarrow \displaystyle \rm{3x + 8 – 4x = 6 } \\ \\ : \longrightarrow \displaystyle \rm{8 – x = 6 } \\ \\ : \longrightarrow \displaystyle \rm{x = 8 – 6 } \\ \\ { \boxed{ \underline{ \huge{ \blue{x = 2}}}}} \\ \\ \sf{Now \: Put \: the \: value \: of \: x \: into \: (1.) } \\ \\ : \longrightarrow \displaystyle \rm{y = 4 – 2(2)} \\ \\ : \longrightarrow \displaystyle \rm{y = 4 – 4} \\ \\ { \boxed{ \underline{ \huge{ \blue{y = 0}}}}}[/tex]

    So, x = 2 and y = 0

    ★VERIFY:-

    Put the values of x and y in these equations:-

    • 2x + y = 4

    [tex]{\boxed{\underline{\displaystyle{\sf{\bf{\red{L.H.S}}}}}}}[/tex]

    [tex] \rm{ = 2(2) + 0} \\ \\ \rm{ = 4}[/tex]

    [tex]{\boxed{\underline{\displaystyle{\sf{\bf{\red{R.H.S}}}}}}}[/tex]

    • 3x + 2y = 6

    [tex]{\boxed{\underline{ \displaystyle{\sf{\bf{\red{L.H.S}}}}}}}[/tex]

    [tex] \rm{ = 3(2) + 2(0)} \\ \\ \rm{ =6 }[/tex]

    [tex]{\boxed{\underline{\displaystyle{\sf{\bf{\red{R.H.S}}}}}}}[/tex]

    Hence, Solved and Verified 🙂

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