NaCl + F2 → NaF + Cl2 determine the number of liters of chlorine gas produced when 3.50 moles of NaCl reacts with excess

1 thought on “NaCl + F2 → NaF + Cl2 determine the number of liters of chlorine gas produced when 3.50 moles of NaCl reacts with excess”

1. Answer:

   156.8 litre

   Explanation:

   Reaction – 2NaCl + F2 = 2NaF + Cl2

   1 Nacl – 3.5 moles of Cl2

   2 Nacl – 7 moles of Cl2

   * Moles of Cl2(n) = V/22.4

   * V = 22.4 x 7

   = 156.8 litre

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