527/224 Explanation: sum of 5/14 and 6/8 [tex] \frac{5}{14} + \frac{6}{8} = \frac{5 \times 4 + 6 \times7 }{56} = \frac{20 + 42}{56} = \frac{62}{56} [/tex] = 31/28 Difference of 11/8 and (-3)/4 [tex] \frac{11}{8} – \frac{( – 3)}{4} = \frac{11 – ( – 3)2}{8} = \frac{11 + 6}{8} = \frac{17}{8} [/tex] Then as per question, [tex] \frac{31}{28} \times \frac{17}{8} [/tex] = 527/224 Reply
527/224
Explanation:
sum of 5/14 and 6/8
[tex] \frac{5}{14} + \frac{6}{8} = \frac{5 \times 4 + 6 \times7 }{56} = \frac{20 + 42}{56} = \frac{62}{56} [/tex]
= 31/28
Difference of 11/8 and (-3)/4
[tex] \frac{11}{8} – \frac{( – 3)}{4} = \frac{11 – ( – 3)2}{8} = \frac{11 + 6}{8} = \frac{17}{8} [/tex]
Then as per question,
[tex] \frac{31}{28} \times \frac{17}{8} [/tex]
= 527/224
Answer:
above mentioned answer is correct!