Moment of force 100N about a point is 20Nm. calculate the distance of point from the force.

20cm

30cm
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1. Answer:

   [tex]\blue{\mathfrak{\underline{\large{Given}}}:} \\ Force(F)=100N \\ Torque(τ) = 20Nm \\ \blue{\mathfrak{\underline{\large{To \: find}}}:} \\ Distance \: of \: point \: from \: force(r) \\ \blue{\mathfrak{\underline{\large{Finding}}}:} \\ \tau = Fr \\ r = \frac{ \tau}{F} \\r = \frac{20}{100} = \frac{1}{5} \: m \\ = \frac{1}{5 } \times 100 \: cm \\ = 20 \: cm \\ \rightarrow \: so \:the \: distance of \: point \: from \: force \\ is \:20 \: cm \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}[/tex]

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