log 64 to the base 2 under root 2 answer this question ❓ it’s so urgent.​

1 thought on “log 64 to the base 2 under root 2 answer this question ❓ it’s so urgent.​”

1. Step-by-step explanation:

   you mean

   [tex] log_{ \sqrt{2} }( 64) [/tex]

   64 =8²=(4*2)²=(√2*√2*√2^4)²=(√2^2*√2^4)²

   =(√2^6)²=(√2)^12

   [tex] log_{ { \sqrt{2} }^{} } \: { \sqrt{2} }^{12} [/tex]

   [tex]12 log_{ \sqrt{2} }( \sqrt{2} ) [/tex]

   [tex]=12[/tex]

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