length of a rectangle is 8meters less than twice its breadth. if the perimeter of the rectangle is 56cm find its length and breadth. please tell me the answer with explanation About the author Remi

Answer: let breadth = x the length =2x-8 given perimeter = 56 cm perimeter = 2(l+b) = 2(2x-8+x) 56/2=3x-8 28=3x-8 36=3x x=12 Reply

Answer: Let length and breadth the field are l and b respectively. Then, l=2b−8⇒2b=8+l⟶(1) The perimeter of the rectangular field =56 m ⇒2(l+b)=56m⇒2l+2b=56m from (1), we get 2l+8+l=56⇒3l=48⇒l=16m ∴ Length of rectangular field =16m Breadth of rectangular field = 2 16+8 =12m Reply

Answer:let breadth = x

the length =2x-8

given perimeter = 56 cm

perimeter = 2(l+b)

= 2(2x-8+x)

56/2=3x-8

28=3x-8

36=3x

x=12

Answer:Let length and breadth the field are l and b respectively. Then,

l=2b−8⇒2b=8+l⟶(1)

The perimeter of the rectangular field =56 m

⇒2(l+b)=56m⇒2l+2b=56m

from (1), we get

2l+8+l=56⇒3l=48⇒l=16m

∴ Length of rectangular field =16m

Breadth of rectangular field =

2

16+8

=12m