length of a rectangle is 8meters less than twice its breadth. if the perimeter of the rectangle is 56cm find its length and breadth. please tell me the answer with explanation About the author Remi
Answer: let breadth = x the length =2x-8 given perimeter = 56 cm perimeter = 2(l+b) = 2(2x-8+x) 56/2=3x-8 28=3x-8 36=3x x=12 Reply
Answer: Let length and breadth the field are l and b respectively. Then, l=2b−8⇒2b=8+l⟶(1) The perimeter of the rectangular field =56 m ⇒2(l+b)=56m⇒2l+2b=56m from (1), we get 2l+8+l=56⇒3l=48⇒l=16m ∴ Length of rectangular field =16m Breadth of rectangular field = 2 16+8 =12m Reply
Answer:
let breadth = x
the length =2x-8
given perimeter = 56 cm
perimeter = 2(l+b)
= 2(2x-8+x)
56/2=3x-8
28=3x-8
36=3x
x=12
Answer:
Let length and breadth the field are l and b respectively. Then,
l=2b−8⇒2b=8+l⟶(1)
The perimeter of the rectangular field =56 m
⇒2(l+b)=56m⇒2l+2b=56m
from (1), we get
2l+8+l=56⇒3l=48⇒l=16m
∴ Length of rectangular field =16m
Breadth of rectangular field =
2
16+8
=12m